(5x^2-20)=(4x-25)=180

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Solution for (5x^2-20)=(4x-25)=180 equation: 



(5x^2-20)=(4x-25)=180

We move all terms to the left:

(5x^2-20)-((4x-25))=0

We get rid of parentheses

5x^2-((4x-25))-20=0



We calculate terms in parentheses: -((4x-25)), so:

(4x-25)

We get rid of parentheses

4x-25

Back to the equation:

-(4x-25)



We get rid of parentheses

5x^2-4x+25-20=0

We add all the numbers together, and all the variables

5x^2-4x+5=0

a = 5; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·5·5
Δ = -84
Delta is less than zero, so there is no solution for the equation

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